Rankwise

Integration of cosec²x

∫ cosec²x dx = −cot x + C

Proof

  1. d/dx(−cot x) = cosec²x.
Check it: differentiate the answer and you should get back cosec²x. C is the constant of integration; leave it out only in definite integrals.

Standard integration formulas

IntegralResult
∫ sin x dx−cos x + C
∫ cos x dxsin x + C
∫ tan x dxlog|sec x| + C
∫ cot x dxlog|sin x| + C
∫ sec x dxlog|sec x + tan x| + C
∫ cosec x dxlog|cosec x − cot x| + C
∫ sec²x dxtan x + C
∫ cosec²x dx−cot x + C
∫ sec x tan x dxsec x + C
∫ cosec x cot x dx−cosec x + C
∫ log x dxx log x − x + C
∫ eˣ dxeˣ + C
∫ aˣ dxaˣ / log a + C
∫ 1/x dxlog|x| + C
∫ xⁿ dxxⁿ⁺¹/(n + 1) + C, n ≠ −1
∫ sin²x dxx/2 − (sin 2x)/4 + C
∫ cos²x dxx/2 + (sin 2x)/4 + C
∫ tan²x dxtan x − x + C
∫ sin³x dxcos³x/3 − cos x + C
∫ sin x cos x dx(sin²x)/2 + C
∫ sec³x dx½(sec x tan x + log|sec x + tan x|) + C
∫ 1/(1 + x²) dxtan⁻¹x + C
∫ 1/√(1 − x²) dxsin⁻¹x + C
∫ 1/(x² + a²) dx(1/a) tan⁻¹(x/a) + C
∫ 1/(x² − a²) dx(1/2a) log|(x − a)/(x + a)| + C
∫ 1/(a² − x²) dx(1/2a) log|(a + x)/(a − x)| + C
∫ 1/√(a² − x²) dxsin⁻¹(x/a) + C
∫ 1/√(x² + a²) dxlog|x + √(x² + a²)| + C
∫ 1/√(x² − a²) dxlog|x + √(x² − a²)| + C
∫ √(a² − x²) dx(x/2)√(a² − x²) + (a²/2) sin⁻¹(x/a) + C
∫ √(x² + a²) dx(x/2)√(x² + a²) + (a²/2) log|x + √(x² + a²)| + C
∫ √(x² − a²) dx(x/2)√(x² − a²) − (a²/2) log|x + √(x² − a²)| + C
∫ x eˣ dx(x − 1)eˣ + C
∫ x sin x dxsin x − x cos x + C
∫ x cos x dxx sin x + cos x + C
∫ x log x dx(x²/2) log x − x²/4 + C
∫ eˣ sin x dx(eˣ/2)(sin x − cos x) + C
∫ eˣ cos x dx(eˣ/2)(sin x + cos x) + C
∫ sin⁻¹x dxx sin⁻¹x + √(1 − x²) + C
∫ tan⁻¹x dxx tan⁻¹x − ½ log(1 + x²) + C
∫ 1/(1 + cos x) dxtan(x/2) + C
∫ 1/(1 + sin x) dxtan x − sec x + C
∫ (log x)/x dx(log x)²/2 + C
∫ 1/(x log x) dxlog|log x| + C
∫ eˣ[f(x) + f′(x)] dxeˣ f(x) + C

Questions students ask

What is the integration of cosec²x?

∫ cosec²x dx = −cot x + C.

How do you integrate cosec²x?

d/dx(−cot x) = cosec²x.

Which method is used to integrate cosec²x?

Standard result.

Use these next