The formula NTA's percentile gives you
Your percentile already tells you what share of students you beat. Turning it into a rank is simple arithmetic:
For 2026, about 15,38,468 unique students appeared. So at 98 percentile: (100 − 98) × 15,38,468 ÷ 100 ≈ 30,769. For 2027 we'll update the number once NTA publishes it; you can change it yourself in the tool.
The rank you get is your Common Rank List (CRL) rank. Your category rank is lower (better), because it only counts students in your category.
Percentile vs rank table
| Percentile | Approx. rank (CRL) |
|---|---|
| 99.99 | 154 |
| 99.9 | 1,538 |
| 99.5 | 7,692 |
| 99 | 15,385 |
| 98.5 | 23,077 |
| 98 | 30,769 |
| 97 | 46,154 |
| 96 | 61,539 |
| 95 | 76,923 |
| 93.4 | 1,01,539 |
| 90 | 1,53,847 |
| 85 | 2,30,770 |
| 80 | 3,07,694 |
Rank for common percentiles
80 percentile85 percentile90 percentile92 percentile94 percentile95 percentile96 percentile97 percentile98 percentile99 percentile99.5 percentile99.9 percentile
See the full percentile vs rank table →
JEE Advanced qualifying cutoff (2026)
About 2,50,182 students qualify for JEE Advanced each year. These were the starting percentiles in 2026. Expect 2027 to be close, give or take a percentile.
| Category | Minimum percentile |
|---|---|
| General (UR) | 93.4124 |
| GEN-EWS | 82.4165 |
| OBC-NCL | 80.9233 |
| SC | 63.9173 |
| ST | 52.0175 |
| PwD (any) | 0.0023 |
Questions students ask
What rank will I get at 95 percentile in JEE Main?
About 76,923, based on 15,38,468 candidates. Your category rank will be lower.
What rank will I get at 99 percentile?
Roughly 15,385 in the Common Rank List.
Is the JEE Main rank calculated from Session 1 or Session 2?
From your best percentile across both sessions. NTA publishes ranks only after Session 2.
What percentile do I need for JEE Advanced?
In 2026, General category students needed 93.41 percentile. OBC-NCL needed 80.92, SC 63.92 and ST 52.02.