Rankwise

Derivative of cosec x

d/dx(cosec x) = −cosec x cot x

Proof

  1. cosec x = (sin x)⁻¹. Chain rule: −(sin x)⁻² × cos x = −(1/sin x)(cos x/sin x) = −cosec x cot x.

Standard derivatives

FunctionDerivative
d/dx(sin x)cos x
d/dx(cos x)−sin x
d/dx(tan x)sec²x
d/dx(cot x)−cosec²x
d/dx(sec x)sec x tan x
d/dx(cosec x)−cosec x cot x
d/dx(eˣ)eˣ
d/dx(aˣ)aˣ log a
d/dx(log x)1/x
d/dx(xⁿ)n xⁿ⁻¹
d/dx(√x)1/(2√x)
d/dx(1/x)−1/x²
d/dx(sin⁻¹x)1/√(1 − x²)
d/dx(cos⁻¹x)−1/√(1 − x²)
d/dx(tan⁻¹x)1/(1 + x²)
d/dx(cot⁻¹x)−1/(1 + x²)
d/dx(sec⁻¹x)1/(|x|√(x² − 1))
d/dx(xˣ)xˣ(1 + log x)
d/dx(logₐx)1/(x log a)
d/dx(sin²x)sin 2x
d/dx(log(sin x))cot x
d/dx(|x|)x/|x| (x ≠ 0)

Questions students ask

What is the derivative of cosec x?

d/dx(cosec x) = −cosec x cot x.

How do you differentiate cosec x?

cosec x = (sin x)⁻¹. Chain rule: −(sin x)⁻² × cos x = −(1/sin x)(cos x/sin x) = −cosec x cot x.

Use these next