Rankwise

Moment of inertia of a rectangular plate (sides a and b) about its central axis

I = M(a² + b²)/12, radius of gyration k = √((a² + b²)/12)

Axis: through the centre, perpendicular to the plate.

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Derivation

  1. About an axis in the plane through the centre and parallel to side b, the plate acts like a rod of length a: Ma²/12.
  2. Likewise about the other in-plane axis: Mb²/12.
  3. Perpendicular axis theorem: I = Ma²/12 + Mb²/12 = M(a² + b²)/12.

Moment of inertia of standard bodies

Questions students ask

What is the moment of inertia of a rectangular plate (sides a and b) through the centre, perpendicular to the plate?

I = M(a² + b²)/12, so the radius of gyration is k = √((a² + b²)/12).

How is the moment of inertia of a rectangular plate (sides a and b) through the centre, perpendicular to the plate derived?

About an axis in the plane through the centre and parallel to side b, the plate acts like a rod of length a: Ma²/12. Likewise about the other in-plane axis: Mb²/12. Perpendicular axis theorem: I = Ma²/12 + Mb²/12 = M(a² + b²)/12.

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